【JAVA】通过JAVA实现用户界面的登录

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consequent on随之而来

文章目录

实参和形参的关系

publicclassTest{publicstaticvoidswap(int a ,int b){int tmp = a;
        a = b;
        b = tmp;}publicstaticvoidmain(String[] args){int x =10;int y =20;swap(x,y);System.out.println(x);System.out.println(y);}}

JAVA 当中无法获取到 局部变量的地址. 实参和形参的关系就像榨汁机一样,丢进去的是橙子,出来的是橙汁.

publicclassTest{publicstaticvoidmain(String[] args){int[] arr ={10,20};swap(arr);System.out.println("arr[0] = "+ arr[0]+"arr[1] = "+ arr[1]);}publicstaticvoidswap(int[] arr){int tmp = arr[0];
        arr[0]= arr[1];
        arr[1]= tmp;}}

虽然数组通过下标可以交换它的位置,但它的内存地址并未发生改变.
所以说,数组不能传某一块的内存地址.

• return 代表法方的结束.
• return后的代码不会被执行.

方法重载

publicclassTest{publicstaticdoubleadd(double d ,double c){return  d + c;}//     Overload 重载publicstaticintadd(int d ,int c){return  d + c;}publicstaticlongadd(long d ,int c){return  d + c;}publicstaticlongadd(long d ,int c ,int b){return  d + c;}publicstaticvoidmain(String[] args){int x =10;int y =20;int ret =add(x, y);System.out.println(ret);double d1 =10.5;double d2 =12.5;double dd =add(d1, d2);System.out.println(dd);}}

根据上面的代码我们可以知道,方法的重载遵循以下原则:
(1)方法名一样.
(2)方法的参数列表不一样[个数,数据类型,顺序]
(3)返回值是否一样,不影响方法重载. ___

EXERCISES1-模拟登录

publicclassX{publicstaticvoidmain(String[] args){int count =3;Scanner scanner =newScanner(System.in);while(count !=0){System.out.println("请输入您的密码");String password = scanner.nextLine();if(password.equals("123456")){System.out.println("登陆成功");return;// 通过 return退出程序}else{System.out.println("输入错误,请重新登录");
                count--;}}System.out.println("程序已退出");}}

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