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总结CTF中常用的一些脚本(可保存)

1.不知道JPG长宽爆破

import zlib
import struct
import binascii
import os
import re

file = 'flag.jpg'
fr = open(file,'rb').read()
#print(fr)
i= fr.find(b'\xff\xc0')

headdata=fr[0:i+5]
heightdata=fr[i+5:i+7]
widthdata=fr[i+7:i+9]
remaindata=fr[i+9::]

print (headdata)
print (heightdata)
print (widthdata)
#print (remaindata)

path=os.getcwd()
tmppath=path+'\\tmppic'
print(tmppath)

if os.path.exists(tmppath):
    os.chdir(tmppath)
else:
    os.mkdir(tmppath)
    os.chdir(tmppath)

n=2001
h=500

heightdata=h.to_bytes(2, 'big')

for w in range(1,n): 
    widthdata=w.to_bytes(2, 'big')

    newfile=headdata+heightdata+widthdata+remaindata
    fw = open(str(w)+'.jpg','wb') 
    fw.write(newfile) 
    fw.close 

2.鼠标流量

nums = []
keys = open('usbdata.txt','r')
result=open('result.txt','w')
posx = 0
posy = 0
for line in keys:
    if len(line) != 12 :#忽略空行
         continue
    x = int(line[3:5],16)
    y = int(line[6:8],16)
    if x > 127 :
        x -= 256
    if y >120 :#这个参数控制单个字符的高度,如果高度过大导致字符过瘦,请调大
        y -=256#这个参数控制字符串的倾斜程度,如果向下倾斜就调高,如果向上倾斜就调低
    posx += x
    posy += y
    btn_flag = int(line[0:2],16)  # 1 for left , 2 for right , 0 for nothing
    if btn_flag == 1 :
        result.write(str(posx)+' '+str(-posy)+'\n')
keys.close()
result.close()

3.base换表爆破

import itertools
def My_base64_decode(inputs,s):
    bin_str = []
    for i in inputs:
        if i != '=':
            x = str(bin(s.index(i))).replace('0b', '')
            bin_str.append('{:0>6}'.format(x))
    #print(bin_str)
    outputs = ""
    nums = inputs.count('=')
    while bin_str:
        temp_list = bin_str[:4]
        temp_str = "".join(temp_list)
        #print(temp_str)
        if(len(temp_str) % 8 != 0):
            temp_str = temp_str[0:-1 * nums * 2]
        for i in range(0,int(len(temp_str) / 8)):
            outputs += chr(int(temp_str[i*8:(i+1)*8],2))
        bin_str = bin_str[4:]    
    return outputs
h=['j','u','3','4']
h1=list(itertools.permutations(h))
for i in h1:
    m="".join(i)
    s = "JASGBWcQPRXEFLbCDIlmnHUVKTYZdMovwipatNOefghq56rs"+m+"kxyz012789+/"
    input_str="mtHVnkLnIaP3FaA7KOWjTmKkVjWjVzKjdeNvTnAjoH9iZOIvTeHbvD=="
    print(My_base64_decode(input_str,s),i)

#NEWSCTF2021{base64_1s_v3ry_e@sy_and_fuN}

4.BMP-填入正确宽度后可自动爆破高度

from PIL import Image
import os
import matplotlib.pyplot as plt

file = '3.bmp'
fr = open(file,'rb').read()
headdata = bytearray(fr[0:18])
widthdata = bytearray(fr[18:22])
heightdata = bytearray(fr[22:26])
remaindata = bytearray(fr[26::])

#请填入正确的宽度和预估最大高度范围
#############################################################
w = 793
n = 2000
#############################################################

h1=int.from_bytes(heightdata,byteorder='little',signed=True)
print(h1)

if h1<0:

    n = -n

    path=os.getcwd()
    tmppath=path+'\\tmppic'
    print(tmppath)

    if os.path.exists(tmppath):
        os.chdir(tmppath)
    else:
        os.mkdir(tmppath)
        os.chdir(tmppath)

    widthdata=w.to_bytes(4, 'little')

    for h in range(-1,n,-1): 
        heightdata=h.to_bytes(4, 'little',signed=True)

    #    print (widthdata)

        newfile=headdata+widthdata+heightdata+remaindata
        fw = open(str(h)+'.bmp','wb') 
        fw.write(newfile) 
        fw.close 

        #img=Image.open(str(h)+'.bmp')

        try:
            img=Image.open(str(h)+'.bmp')
            print(h)

            plt.figure(figsize=(4, 4))
            plt.ion()  # 打开交互模式
            plt.axis('off')  # 不需要坐标轴
            plt.imshow(img)
             
            mngr = plt.get_current_fig_manager()
            #mngr.window.wm_geometry("+380+310")  # 调整窗口在屏幕上弹出的位置
            #plt.pause(1)  # 该句显示图片1秒
            plt.ioff()  # 显示完后一定要配合使用plt.ioff()关闭交互模式,否则可能出奇怪的问题
             
            plt.clf()  # 清空图片
            plt.close()  # 清空窗口

            #os.remove(str(h)+'.bmp')
        except TypeError as e:

            print('except:', e)

            j=h+1
            break    

        except OSError as e:

            print('except:', e)

            j=h+1
            break
    print(j)

else:
    #n = 1000

    path=os.getcwd()
    tmppath=path+'\\tmppic'
    print(tmppath)

    if os.path.exists(tmppath):
        os.chdir(tmppath)
    else:
        os.mkdir(tmppath)
        os.chdir(tmppath)

    widthdata=w.to_bytes(4, 'little')

    for h in range(1,n): 
        heightdata=h.to_bytes(4, 'little',signed=True)

    #    print (widthdata)

        newfile=headdata+widthdata+heightdata+remaindata
        fw = open(str(h)+'.bmp','wb') 
        fw.write(newfile) 
        fw.close 

        img=Image.open(str(h)+'.bmp')

        try:

            #print(h)

            plt.figure(figsize=(4, 4))
            plt.ion()  # 打开交互模式
            plt.axis('off')  # 不需要坐标轴
            plt.imshow(img)
             
            mngr = plt.get_current_fig_manager()
            #mngr.window.wm_geometry("+380+310")  # 调整窗口在屏幕上弹出的位置
            #plt.pause(1)  # 该句显示图片1秒
            plt.ioff()  # 显示完后一定要配合使用plt.ioff()关闭交互模式,否则可能出奇怪的问题
             
            plt.clf()  # 清空图片
            plt.close()  # 清空窗口

            #os.remove(str(h)+'.bmp')
        except TypeError as e:

            print('except:', e)

            j=h-1
            break    

        except OSError as e:

            print('except:', e)

            j=h-1
            break
    print(j)

5.爆破多个压缩包crc

#爆破多个压缩包的crc
#长度为4字节
import zipfile
import string
import binascii
path = 'D:\\IDM_download\\file_17\\out'#输入文件夹目录

crcs = [''] * 68#压缩包总个数
txts = [''] * 68#同上

for i in range(68):
    file = path + str(i) + '.zip'
    f = zipfile.ZipFile(file, 'r')
    crcs[i] = f.getinfo('data.txt').CRC

dic = string.printable[:-6]
num = 0
for i in dic:
    for j in dic:
        for k in dic:
            for l in dic:
                s = i + j + k + l
                c = binascii.crc32(s.encode('utf-8'))
                for n in range(68):
                    if c == crcs[n]:
                        txts[n] = s
                        print('No.%d is %s' %(n, s))
                        num += 1
                if num == 68:
                    print(txts)
                    print(''.join(txts))
                    break
            else:
                continue
            break
        else:
            continue
        break
    else:
        continue
    break

6.棋盘密码替换爆破


import itertools
s0="abcdefghiklmnopqrstuvwxyz"
s1=["11","12","13","14","15","21","22","23","24","25","31","32","33","34","35","41","42","43","44","45","51","52","53","54","55"]
s2=["1","2","3","4","5"]
s4="iftffsissrssirissr"
s3=["f","i","r","s","t"]
s3=list(itertools.permutations(s3))
for k in s3:
    S=""
    for i in range(0,len(s4),2):
       x=""
       for j in s4[i:i+2]:
           x+=s2[list(k).index(j)]
       S+=s0[s1.index(x)]
    print(S)
    
#keyisthis

7.cipin词频统计

做一个词频统计程序,该程序具有以下功能
基本要求:
(1)可导入任意英文文本文件
(2)统计该英文文件中单词数和各单词出现的频率(次数),并能将单词按字典顺序输出。
(3)将单词及频率写入文件。
提高要求:
完成基本要求的基础上,实现下述功能:
1.实现GUI界面。
2.将单词及频率写入数据库。

实现思路:

定义一个单词容器类wordcol,有两个属性,第一个属性为单词本身,第二属性就是出现次数。用一个map来统计,map的key为单词本身,value为wordcol对象。先将一篇文章清洗干净,过滤掉所有的标点符合等,这个用正则表达式即可。然后将大写的字母小写,因为大写和小写不形象单词本身的出现次数,再将单词按照空格分割,分割后得到一个数组就是所有的单词,但是可能包含空格。所以在统计的时候加以判断。

经典分拣思路:

遍历这一堆单词数组,每次取出一个单词,用map的get方法获得value值。如果value为空,则说明,这个单词还没有被统计过,则创建一个新的wordcol,次数为1,然后加入到map中。如果不为空则将获得到的value即wordcol对象中的次数属性加一。加了一个单词首字母排序的功能,即将key进行一个排序,然后按照排序后的key输出,或者直接用treemap。

import re

file = open('flag.txt')
line = file.readlines()
file.seek(0,0)
file.close()

result = {}
for i in range(97,123):
    count = 0
    for j in line:
        find_line = re.findall(chr(i),j)
        count += len(find_line)
    result[chr(i)] = count
res = sorted(result.items(),key=lambda item:item[1],reverse=True)

num = 1
for x in res:
        print('频数第{0}: '.format(num),x)
        num += 1 

8.LSB按行读取rgb转换0和1

from PIL import Image
im=Image.open('gray.png')
width=im.size[0]
height=im.size[1]
fh=open('1.txt','w')
for h in range(height):
    for w in range(width): 
     
        color=im.getpixel((w,h))
#        print color
        colorsum=color[0]+color[1]+color[2]
        if(colorsum == 0):
            fh.write('1')
        else:
            fh.write('0')
    
fh.close()

9.根据RGB数值自动因式分解画图

from PIL import Image

def Crack(n):#yinshufenjie
    flag = []
    for each in range(2,int(n **0.5)+1):
        if(n % each == 0):
            print(each,int(n/each))
            flag += [(each,int(n/each))]
    if len(flag) == 1:return flag[0]
    else:
        choice = input("Which group to select(0-%s):"%(len(flag)-1))
        return flag[int(choice)]
def Paint(X,Y,listrgb):#Draw according to string list
    pic = Image.new("RGB",(X, Y))
    i=0
    for x in range (0,X):   
        for y in range (0,Y):
            temp = listrgb[i].split(',')
            pic.putpixel([x,y],(int(temp[0]),int(temp[1]),int(temp[2])))
            i = i+1
    pic.show()
    pic.save(r"/root/flag%s.png"%(X))
listrgb = open(r"/root/1.txt").readlines()
X,Y = Crack(len(listrgb))
Paint(X,Y,listrgb)
Paint(Y,X,listrgb)

10.批量提取文件名

@echo off

for /f "delims=" %%a in ('dir /b/a-d/oN *.*') do echo %%a >>1.txt

11.还原图片

from PIL import Image

x = 320
y = 245

im = Image.new('RGB', (x, y))
with open('hint.txt') as f:
    for i in range(x):
        for j in range(y):
            line = f.readline().replace('\n','')
            s = line.split(',')
            im.putpixel((i, j), (int(s[0]), int(s[1]), int(s[2])))
im.save('d.png')

12.根据图像点画图

60
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img0 = Image.new('RGB', (1000, 1000), '#ffffff')
for i in range(len(s)):
    for j in range(20):
        for n in range(20):
            img0.putpixel ((s[i]+j,t[i]+n), (0,0,0))
img0.save("result.png")

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