1、语法:regexp_replace(subject,pattern,str)
注:subject,pattern,str都为字符串,subject为被替换的字符串,pattern为正则表达式,str需要替换的字符串。
2、表描述:表explode_test,表头(area,good_id,sale_info)
a:shangdong,b:beijing,c:shanghai 1,2,3 [{"source":"7fresh","monthSales":4900,"userCount":1900,"score":"9.9"},{"source":"jdmart","monthSales":7900,"userCount":2900,"score":"5.9"},{"source":"yam","monthSales":54900,"userCount":12900,"score":"4.9"}]
a:tianjing,b:beijing,c:shanghai 3,4,5 [{"source":"7fresh","monthSales":4900,"userCount":1900,"score":"9.9"},{"source":"jdmart","monthSales":7900,"userCount":2900,"score":"5.9"},{"source":"yam","monthSales":54900,"userCount":12900,"score":"4.9"}]
3、去掉sale_info的【】
select regexp_replace(sale_info, '\[ | \]' , '') —— “|”是或的意思
from explode_test;
4、切分取出数据
select explode(split(regexp_replace(sale_info, '\[\{|\}\]' ), '\},\{' ))
from explode_test;
5、变成结构化表
select
split(split(a.col,',')[0],':')[1] as source,
split(split(a.col,',')[1],':')[1] as monthSales,
split(split(a.col,',')[2],':')[1] as userCount,
split(split(a.col,',')[3],':')[1] as score
from
(select explode(split(regexp_replace(sale_info,'\\[\\{|\\}\\]',''),'\\},\\{')) as col from explode_test) a;
6、get_json_object实现
将数据变成字典形式,然后用get_json_object提取数据。
select
get_json_object ( a.col, '$.source' ) as source,
get_json_object (a.col, '$.monthSales' ) as monthSales,
get_json_object (a.col, '$.userCount' ) as userCount,
get_json_object (a.col, '$.score' ) as score
from
(select
explot(split(regexp_replace(regexp_replace(sale_info, '\[|\]',''),, '\}\,\{', '\}\;\{'), '\;')) as col
from explode_test) a;
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